6m^2+8m-25=3

Solution for 6m^2+8m-25=3 equation:

6m^2+8m-25=3

We move all terms to the left:

6m^2+8m-25-(3)=0

We add all the numbers together, and all the variables

6m^2+8m-28=0

a = 6; b = 8; c = -28;
Δ = b2-4ac
Δ = 82-4·6·(-28)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{46}}{2*6}=\frac{-8-4\sqrt{46}}{12}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{46}}{2*6}=\frac{-8+4\sqrt{46}}{12}
$